If the length of the rectangle is twice the width, and the perimeter of the rectangle is 30m, what is length and width of the rectangle

The length of the rectangle=10 m

The width of the rectangle=5 m

Step-by-step explanation:

Step 1: Determine the dimensions of the rectangle

let the width of the rectangle be;

width=w

length=2×w=2 w

Step 2: Determine the perimeter of the rectangle

P=2(L+W)

where;

P=perimeter of the rectangle

L=length of the rectangle

W=width of the rectangle

In our case;

P=30 m

L=2 w

W=w

replacing;

2(2 w+w)=30

4 w+2 w=30

6 w=30

w=30/6=5

w=5 m

The length of the rectangle=5×2=10 m

The width of the rectangle=5 m

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )