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![8\times[\frac{1}{8}-10(\frac{3}{4}-\frac{3}{8}x)+\frac{5}{8}x]=8\times-\frac{1}{8}(59-35x)\\\\\frac{8}{8}-80(\frac{3}{4}-\frac{3}{8}x)+\frac{5\times8}{8}x=-\frac{8}{8}(59-35x)\\\\](/tpl/images/0384/2609/3d885.png)
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1/8-10(3/4-3/8x)+5/8x equal to -1/8(59-35x)...
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