2x-6y=12
-6x-4y=-14
use the elimination method to solve. pls i'm desperate.

x=3 and y=−1 AND/OR (3, 1)

Step by Step:

 1) Multiply the first equation by 3, and multiply the second equation by 1.

 3(2x−6y=12)

 1(−6x−4y=−14)

2) Becomes:

 6x−18y=36

 −6x−4y=−14

3) Add these equations to eliminate x:

 −22y=22

4) Then solve −22y = 22 for y:

 −22y−22=22−22 (Divide both sides by -22)

       y=−1

5) Now that we've found y let's plug it back in to solve for x.

6) Write down an original equation:

 2x−6y=12

7) Substitute−1for y in2x−6y=12:

2x − (6) (−1) =12

2x + 6 = 12 (Simplify both sides of the equation)

2 x + 6 + − 6 = 12 + −6 (Add -6 to both sides)

2 x = 6

2 x 2 = 62 (Divide both sides by 2)

x = 3