Aball is thrown vertically upward from ground level with an initial velocity of 80 feet per second. the ball's h height after t seconds is given by the equation h = −16t2 + 80t. how long will it take for the ball to hit the ground?

The ball will take 5 seconds to hit the ground.

Step-by-step explanation:

The ball's h height after t seconds is given by the equation h = −16t² + 80t

When the ball hit the ground, the height will be zero.

∴ h = −16t² + 80t = 0

∴ −16t² + 80t = 0    take t as common

t ( -16t + 80) = 0

∴ t = 0  Or   -16t + 80 = 0

-16t + 80 = 0

-16t = -80

t = -80/-16 = 5 seconds

So, The ball will take 5 seconds to hit the ground.

you need to show the graph

step-by-step explanation:

idk

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