What is the range of the relation described by the set of ordered pairs {(–2, 0), (–1, 2), (0, 1), (4, 9), (5, –3)}?
{–2, –1, 4, 5, 9}
{–3, –2, –1, 0, 4}
{–3, 0, 1, 2, 9}

We want to find the range of the given relation.

The range is:

{-3, 0, 1, 2, 9}

First, we describe a relationsip as "something" that maps elements from a set, the domain, into elements from another set, the range.

Such that this is represented with pairs (x, y).

That pair means that the element x, which belongs to the domain, is being mapped into the element y, which belongs to the range.

So to find the range of our relation:

{(–2, 0), (–1, 2), (0, 1), (4, 9), (5, –3)}

We just need to find the set that contains all the second values of each pair, this set is:

{0, 2, 1, 9, -3}

Writing the elements in order from least to greatest we have:

{-3, 0, 1, 2, 9}

This is the range of the given relationship.

If you want to learn more, you can read:

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Range = {-3,0,1,2,9}

Step-by-step explanation:

Whenever we are given a relation in the form of set of ordered pairs, we can say that the domain is the set of "x" values and the range is the set of y-values.

The ordered pair is given in the form:

(x,y)

So, the first point is the x coordinate (domain points), and

the second point is the y coordinate (range points).

The set given is:

{(–2, 0), (–1, 2), (0, 1), (4, 9), (5, –3)}

Looking at the 2nd points in each pair, we can say the range is:

0, 2, 1, 9, -3

Arranging for least to greatest, we have:

Range = {-3,0,1,2,9}

how am i supposed to answer

step-by-step explanation:

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.