Aconsumer organization estimates that over a 1-year period 20% of cars will need to be repaired once, 8% will need repairs twice, and 2% will require three or more repairs. if you own two cars, what is the probability that a) neither will need repair? b) both will need repair? c) at least one car will need repair?

Probability that a car need to be repaired once = 20% = 0.20

Probability that a car need to be repaired twice = 8% = 0.08

Probability that a car need to be repaired three or more = 2% = 0.02

a) If you own two cars what is the probability that  neither will need repair?

Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3

Probability that car need no repair = 1-0.3=0.7

Neither car will need repair=

b) both will need repair?

Probability both will need repair =

c)at least one car will need repair

Neither car will need repair=

Probability that at least one car will need repair= 1-0.49 = 0.51

answer: the correct one is a

step-by-step explanation:

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.