In a sample of 593 new websites registered on the internet, 28 were anonymous (i. e., they shielded their name and contact information).

(a) construct a 95 percent confidence interval for the proportion of all new websites that were anonymous. (round your answers to 4 decimal places.)
(b) may normality of p be assumed?

a)

b)Yes

Step-by-step explanation:

n = 593

x = 28

Confidence level = 95%

So, at 95% = 1.96

Formula of confidence interval of one sample proportion:

=

=

=

Hence a 95 percent confidence interval for the proportion of all new websites that were anonymous is

b)  May normality of p be assumed?

Condition for normality : np>10 and np(1-p)>10.

and

27.871  and 26.561063

Hence p is assumed to be normal since the condition is satisfied

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

d. vertex

step-by-step explanation: