Suppose a network has 40 computers of which 5 fail. (a) how many possibilities are there for the five that fail? (b) suppose that 3 of the computers in the network have a copy of a particular file. how many sets of failures wipe out all the copies of the file? that is, how many 5-subsets contain the three computers that have the file?

a) 658008, b) 666.

Step-by-step explanation:

Since we have given that

Total number of computers = 40

Number of failed computers = 5

(a) How many possibilities are there for the five that fail?

We will use "Combination" to find all 5 failed.

(b) Suppose that 3 of the computers in the network have a copy of a particular file. How many sets of failures wipe out all the copies of the file?

So, number of computers failed left = 5-3 =2

Total number of computers = 40-3=37

So, the number of set of failures wipe out would be

Hence, a) 658008, b) 666.

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.