Let x1, x2, and x3 represent the times necessary to perform three successive repair tasks at a certain service facility. suppose they are independent, normal rv's with expected values μ1, μ2, and μ3 and variances σ12, σ22, and σ32, respectively. if μ1=μ2 = μ3=70 and σ1^2=σ2^2=σ3^2=21, calculate p(to < 231) and p(168 < t< 231).

y + 11 = (1/4)(x + 16)

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

25/14 or 1.

step-by-step explanation:

the dots mean that it has infinitely more numbers behind it