Explain the difference between using the sine ratio to solve for a missing angle in a right triangle versus using the cosecant ratio.

see the explanation

Step-by-step explanation:

Let

X > the missing angle in a right triangle

a > the adjacent side to the angle X

b > the opposite side to the angle X

c > the hypotenuse o the right triangle (greater side)

we know that

The sine ratio of angle X is equal to divide the opposite side to angle X by the hypotenuse

so

The cosecant is the reciprocal of the sine

so

therefore

The cosecant ratio of angle X is equal to divide the hypotenuse by the opposite side to angle X

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.