Write the equation of a line that is perpendicular to y=75x+6y=\dfrac{7}{5}x+6y=57x+6y, equals, start fraction, 7, divided by, 5, end fraction, x, plus, 6 and that passes through the point (2,−6)(2,-6)(2,− 2, comma, minus, 6, ).

The equation of a line that is perpendicular to and that passes through the point (2, −6) is .

Step-by-step explanation:

If a linear equation is written in this form , m represents the slope and b represents the y-intercept.

When one line has a slope of , a perpendicular line has a slope of .

We know the slope/intercept equation of the line , the slope of this equation is and the negative reciprocal of that slope is:

The perpendicular line will have a slope of:

we use the point given (2, -6) to find the equation of the perpendicular line

and we solve for y

The equation of a line that is perpendicular to and that passes through the point (2, −6) is .

We can check our work with the graph of the two lines.