Cora says he dosen't need to know the y-interce of a line to write its equation, just its slope and some other point on the line. is she correct? explain. if cora is correct, explain how to find the equation of a line with a slope of -1/3 that includes the point (2,6)

Yes, Cora is correct.

The equation of line with point  (2,6) and slope of line (-1/3)

is x + 3y - 20 = 0

Step-by-step explanation:

Yes, the equation of a line can be written using a point and a slope of the line equation.

Cora has used the POINT SLOPE FORMULA, to represent the line equation.

In Point Slope formula:

The equation with slope m and points (x0,y0) can be written as:

(y-y0) =m (x-x0)

Here, the point (x0,y0) = (2,6)

and slope m = (-1/3)

So, the equation can be written as:

Hence, the equation of line with point  (2,6) and slope of line (-1/3)

is x + 3y - 20 = 0

mk./km: lm

step-by-step explanation:

,mlmlm

; mk

lk

step-by-step explanation:

in which figure is point g a centroid