If joe finished half of his homework questions at school and completed one-third after practice, how many problems did joe start with if he has 13 to finish

78 problems

Step-by-step explanation:

Let x = the total number of problems that Joe started with. Joe finished half of his homework questions at school. This means that he finished 1/2 × x = x/2 of the home work at school. What he has left is x - x/2 = x/2.

He completed one-third after practice. This means he completed 1/3 × x = x/3 after practice The number of problems left altogether would be total number of problems - the the sum of the amount he finished at school and the amount he completed after practice. It would be x -(x/2 + x /3) = x - 5x/6 = x/6

If he has 13 to more to finish, that means

x/6 = 13

x = 13×6 = 78 minutes

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

answer: procent 54 wynosi 33,33%