Abox with an open top has a square base and four sides of equal height. the volume of the box is 96 ft³. the height is 2 ft greater than both the length and the width. if the surface area is 112 ft², what are the dimensions of the box?

Dimension of box = 4 ft x 4 ft x 6 ft

Step-by-step explanation:

Let a be the base side of square, and h be the height.

The height is 2 ft greater than both the length and the width.

                h = a + 2

The volume of the box is 96 ft³.

         Volume = Base area x Height = a² x h = a² x (a+2)  

           a² x (a+2)  = 96

           We will get a = 4 ft

Dimension of box = 4 x 4 x (4+2) = 4 ft x 4 ft x 6 ft

no solution

step-by-step explanation:

there is not enough information in the problem to solve.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~