Find an equation for a quartic function containing the following points: (2, 60), (-3, 0), (-1, 0), (4, 0), (1, 0).
put the steps that you did to find the quartic function of the points.

f(x) = -2(x + 3)(x + 1)(x - 4)(x - 1)  or

f(x) = -2x^4 + 2x^3 + 26x^2 - 2x  -24.

Step-by-step explanation:

The zeros of the function are  at (-3, 0), (-1, 0), (4, 0), (1, 0) so in factor form the function is:

a(x + 3)(x + 1)(x - 4)(x - 1)      where a is some constant.

We find a by substituting the point (2, 60)

60 = a(2+3)(2+1)(2-4)(2-1)

-30a = 60

a = -2.

So the function is -2(x + 3)(x + 1)(x - 4)(x - 1) .

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2