What is the standard form of y=-(x-2)(x-3)(x-2)?

y=-x^3+7x^2-16x+12

Step-by-step explanation:

y=-(x-2)(x-3)(x-2)

y=-(x^2-2x-3x+6)(x-2)

y=-(x^2-5x+6)(x-2)

y=-(x^3-5x^2+6x-2x^2+10x-12)

y=-(x^3-7x^2+16x-12)

y=-x^3+7x^2-16x+12

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

correct answer is c. just did it

step-by-step explanation: