Suppose a bag contains 4 white chips and 6 black chips. what is the probability of randomly choosing a black chip, not replacing it, and then randomly choosing another black chip?

a. 9/25
b. 4/25
c. 1/3
d. 2/15

Option C

The probability of randomly choosing a black chip, not replacing it, and then randomly choosing another black chip is

A bag contains 4 white chips and 6 black chips .

So, total number of chips are 10

We have to find the probability of randomly choosing a black chip, not replacing it, and then randomly choosing another black chip

Let A be the event of randomly choosing a black chip out of total 10 chips can be written as:-

Let B be the next successive event in which the black chip is not replaced, so we are left with 4 White chips and 5 Black Chips

Now the probability of happening this event is :

Since, these are successive cases so total probability is:

Hence, the probability of happening given event is

Thus option C is correct

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

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step-by-step explanation: