Aright triangle has a hypotenuse length of 13 units. one leg has a length of 12 units. which equation can be used to determine the length of the other leg?
group of answer choices

latex: a^2=12^2+13^2 a 2 = 12 2 + 13 2

latex: a=\sqrt{13^2-12^2} a = 13 2 − 12 2

latex: a^2=12^2-13^2 a 2 = 12 2 − 13 2

latex: a=\sqrt{12^2+13^2} a = 12 2 + 13 2

We know that a²+b²=c²

So if you follow the pythagorean theorem,  we substitute the hypotenuse for c² and the leg (12) for either a² or b² because a and b are both legs, so it doesn't matter.

now we have a²+12²=13²  

But I usually take the shortcut..and instead of a²+12²=13²

I subtract 12² from 13² (it's the same thing)

After you subtract 13²-12²=a²...you find the square root of 13²-12²

so the answer is LaTeX: a=\sqrt{13^2-12^2}

a= square root of 13²-12²

add an !

step-by-step explanation:

you would need to know all the numbers that are on there

step-by-step explanation: