Acertain list consists of 21 different numbers. if n is in the list and n is 4 times the average(arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?
(a) 1/20
(b) 1/6
(c) 1/5
(d) 4/21
(e) 5/21

B.

Step-by-step explanation:

Let x be the sum of the 21 numbers,

In which n is one of the numbers,

Since,

So, the average of 20 numbers excluded n =

According to the question,

Hence, OPTION 'B' is correct.

stop using this to cheat on home work

step-by-step explanation:

dfbvfvdf

4444444444444 i think