In a competition between players x and y, the first player to win three games in a row or a total of four games wins. how many ways can the competition be played if x wins the first game and y wins the second and third games? (hint: draw a tree.)

The competition can be played in 7 different ways

Step-by-step explanation:

First game : X

Second game : Y

Third game : Y

After that either X or Y can win

The competition ends with Y winning as he/she won 3 games in a row

more games are required to decide the winner

more games are required to decide the winner

The competition ends with X winning as he/she won 3 games in a row

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

more games are required to decide the winner

The competition ends with Y winning as he/she won 4 games in total

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

∴The competition can be played in 7 different ways

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.