Plll !
the following is a rhombus, therefore angle cda is congruent to angle bda.

The statement is true

Step-by-step explanation:

we know that

In a Rhombus the diagonals bisect opposite angles.

therefore

diagonal AD bisect angle D and angle A

so

m∠CDA≅m∠BDA

m∠CAD≅m∠BAD

diagonal CB bisect angle C and angle B

so

m∠ACB≅m∠DCB

m∠ABC≅m∠DBC

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i