the distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t^2 where d equals the distance traveled at time t seconds and t equals the time in seconds. what does the average rate of change of d(t) from t = 3 to t = 6 represent?

a. the coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds.

b. the coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds.

c. the coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.

d. the coin travels an average distance of 14.7 meters from 3 seconds to 6 seconds.

C. The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.

Step-by-step explanation:

If t=3 or t=6 take the 3 and replace it for t. d(3)= 4.9(3)^2= 44.1 so with that answered you can now narrow the answer down to A. and C. so if we go back to the question the coin was dropped from the top of a building that then narrows it down to C.

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.  

step-by-step explanation:

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