During the 2007 baseball season, wade was up to bat 10 more times than
his teammate dwight. dwight batted 17 fewer times than another
teammate, ellis. the three players were up to bat a total of
1650 times. how many times did ellis come to bat?

The number of times Ellis get to bat  is  558.

Step-by-step explanation:

Here, let us assume the number of times Ellis bat = m

So, the number of times Dwight bat =  17 times fewer than Ellis

                                                            = m - 17

Also, number of times Wade got to bat  = 10 more times than Dwight

= ( m- 17 )+ 10

Total number of bat times = 1650

So, the number of times ( Wade + Dwight + Ellis) bat together = 1650

⇒   ( m- 17 )+ 10 + (m - 17) + m =  1650

or, 3 m - 34 + 10 =  1650

or, 3  m = 1674

⇒ m = 1674/3 = 558 , or m = 558

Hence, the number of times Ellis get to bat = m = 558.

where is the graph

step-by-step explanation:

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .