Find the equation that has 2, 1, and -1 as roots

(x-2)(x-1)(x+1)

Step-by-step explanation: Roots are where the graph hits the x-axis. So just like if you had the equation (example) x^2 + 4x + 4 and you were to factor it out to get (x+2)(x+2) you could then set x+2=0 to get the root x=-2. Think of your problem like as if someone has already done the factoring for you. Now all you have to remember is that the answer will have the opposite sign with in the parentheses because its like you’re adding or subtracting it to the x to get zero on other side of the equal sign... x=3 ——> x-3 = 0

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation:

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft