Personnel selection. suppose that 7 female and 5 male applicants have been successfully screened for 5 positions. if the 5 positions are filled at random from the 12 âfinalists, what is the probability of selecting â

(a) 3 females and 2â males? â
(b) 4 females and 1â male? â
(c) 5â females?
â(d) at least 4â females?

(A) 0.4419

(B) 0.2209

(C) 0.0265

(D)  0.2474

Step-by-step explanation:

Given,

Females = 7,

Males = 5,

Total candidates = 7 + 5 = 12,

The total ways of choosing any 5 candidates =

(A) Number of ways of choosing 3 females and 2 males =

Since,

Thus, the probability of choosing 3 females and 2 males =

Similarly,

(B)

The probability of choosing 4 females and 1 male =

= 0.2209

(C)

The probability of choosing 5 females =

= 0.0265

(D)

The probability of choosing at least 4 females =

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x

step-by-step explanation:

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