Acar is traveling at 98 km/h when the driver sees an accident 85 m ahead and slams on the brakes. what minimum constant deceleration is required to stop the car in time to avoid a pileup?

-56494.12km/h2

Step-by-step explanation:

We use one of the equations of motion to answer this question, preferably for one that has all the parameters we've been given

v2-u2=2as

v=final speed = 0

u=initial speed = 85km/h

s=distance = 85m =0.085km

a=acceleration

Then we make a the subject of formula

a=(v2-u2)/2s

Inputting all our values

a = -56494.12km/h2

the negative sign shows that it's decelerating

So therefore

deceleration = 56494km/h2

The workings is in the picture I sent

could

step-by-step explanation:

u send me a picture of ur work

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !