Arectangles length x is 2 meters greater than it’s width if the perimeter of the rectangle is greater than 112 meters what is the rectangles possible length x in meters

The length must be greater than 29 m

Step-by-step explanation:

Length of the rectangle: x. It must be 2 meters greater than its width w, so

x = w + 2

Perimeter of a rectangle = sum of its sides = 2*x+2*w

P = 2(w+2)+2w = 4+4w

The perimeter must be greater than 112 m, so

4+4w > 112

4w > 108

w > 27, or

x - 2 > 27

x > 29

The length must be greater than 29 m

1,589.63 in.^3

step-by-step explanation:

i hope this you : d

answer: i guess 105 degrees?

step-by-step explanation: