Arectangle is 4 times as long as it is wide. the perimeter is 150cm. find the dimensions of the rectangle. round to the nearest tenth if necessary

Length 60 cm

Width 15 cm

Step-by-step explanation:

Let

x ----> the length of rectangle

y----> the width of rectangle

we know that

The perimeter of rectangle is equal to

we have

so

simplify

----> equation A

----> equation B

substitute equation B in equation A

solve for y

Find the value of x

----->

therefore

The dimensions of the rectangle are

Length 60 cm

Width 15 cm

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.