The mean annual tuition and fees for a sample of 12 private colleges was $36,800 with a standard deviation of $5000. a dotplot shows that it is reasonable to assume that the population is approximately normal. you wish to test whether the mean tuition and fees for private colleges is different from $33,700 compute the value of the test statistic and state the number of degrees of freedom. a) 0.620; 12 degrees of freedom b) 0.620; 11 degrees of freedom c) 2.148; 12 degrees of freedom d) 2.148: 11 degrees of freedom

The value of the test statistic and the number of degrees of freedom is 2.148 and 11 respectively.

Step-by-step explanation:

The mean annual tuition and fees for a sample of 12 private colleges was $36,800 with a standard deviation of $5000

n = 12

Claim: You wish to test whether the mean tuition and fees for private colleges is different from $33,700

Since n < 30 and sample standard deviation is given so, we will use t test

Formula :

Substitute the values in the formula :

Degree of freedom = n-1 = 12-1 =11

So,. Option D is true

Hence the value of the test statistic and the number of degrees of freedom is 2.148 and 11 respectively.

answer: procent 54 wynosi 33,33%

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet