Suppose a corrections officer in ohio wants to test the claim that the average time convicted armed burglars with no prior convictions spend in jail is 106.8 months with a standard deviation of 24 months. he collects data for a random sample of 49 such cases from court files and determines that the mean jail time is 112.7 months. the officer conducts a two-tailed one-sample zz‑test for a mean with the following null (h0)(h0) and alternative (h1)(h1) hypotheses, where μ is the mean number of months armed burglars with no prior convictions spend in jail. h0: : =106.8≠106.8h0: μ=106.8h1: μ≠106.8the corrections officer determines that the 90% confidence interval is 107.06< < 118.34107.06< μ< 118.34 months. based on the confidence interval, what decision should the police officer make about his hypothesis test? 1.the officer should reject h0h0 at the 5% significance level because the null hypothesis value is less than the lower limit the confidence interval.2.the officer should fail to reject h0h0 at the 5% significance level because the null hypothesis value is not within the confidence interval.3.the decision to reject or fail to reject h0h0 cannot be determined from the given information.4.the officer should fail to reject h0h0 at the 10% significance level because the null hypothesis value is not within the confidence interval.5.the officer should reject h0h0 at the 10% significance level because the null hypothesis value is not within the confidence interval.