Mathematics, 27.11.2019 01:31 AyeSmoky
An arch is 630 ft high and has 580=ft base. it can be modeled by the parabola =630\left [ 1-\left ( x/290 \right )^2 \right ]. find the average height of the arch above the ground.
the average height of the arch is ft above the ground.
Answers: 1
![y=630[1-\left(\frac{x}{290}\right)^{2}]](/tpl/images/0392/4643/c9c4f.png)
![630[1-\left(\frac{x}{290}\right)^{2}]=0](/tpl/images/0392/4643/214ff.png)
![\text{Average height}=\dfrac{1}{290-(-290)}\int\limits^{290}_{-290} 630[1-\left(\frac{x}{290}\right)^{2}]dx](/tpl/images/0392/4643/b36a3.png)
![\text{Average height}=\dfrac{630}{580}[\int\limits^{290}_{-290} 1dx -\int\limits^{290}_{-290} \left(\frac{x}{290}\right)^{2}dx]](/tpl/images/0392/4643/96c7b.png)
![\text{Average height}=\dfrac{63}{58}[[x]^{290}_{-290}-\frac{1}{84100}\left[\frac{x^3}{3}\right]^{290}_{-290}]](/tpl/images/0392/4643/ee125.png)
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An arch is 630 ft high and has 580=ft base. it can be modeled by the parabola =630\left [ 1-\left (...
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