Do the graphs of 4y=(x-3)^2 and 3x-y=14 intersect at (5,1)

it will happen if both y and x components be equal

so

y= (x-3)²/4 , y = 3x- 14

3x - 14 = (x-3)²/4

12x - 56 = x²-6x + 9

x² - 18x + 65 = 0

delta = 18²-4*65 = 64

x1 = (18 + (64)^(1/2))/2 = 13

x2 = (18 - (64)^(1/2))/2 = 5

one point is x = 5 but we should check if on that point y component is 1 or not

y = (5-3)²/4 = 1

so the functions will intersect at (5,1)

your answer is 23/2 - 13.5

step-by-step explanation:

7/2 evaluates to

multiply x and 4.5

multiply x and 1

the x just gets copied along.

the answer is x

x

4.5*x evaluates to 4.5x

multiply 3 and 4.5x

multiply 1 and x

the x just gets copied along.

x

4.5*x*3 evaluates to 13.5x

7/2-4.5*x*3 evaluates to

  + 8 =

the answer is

7/2-4.5*x*3+8 evaluates to

dhhghghghhrhbb it 5

d

step-by-step explanation: