You have this information about δabc, δdef, and δghi:

ab = df

ab = gi

bc = hi

de = hi

m∠b = m∠d = m∠i

which triangles must be congruent?
δabc and δdef only

δghi and δabc only

none of the triangles
δabc, δdef, and δghi

ΔABC, ΔDEF, and ΔGHI

Step-by-step explanation:

Given: In ΔABC, ΔDEF, and ΔGHI:

AB = DF               AB = GI

BC = HI                DE = HI

m∠B = m∠D = m∠I

In ΔABC and ΔGHI

AB = GI  [given]

BC = HI  [given]

m∠B =  m∠I  [given]

[ here m∠B and m∠I are the included angle of ΔABC and ΔGHI]

∴ ΔABC ≅ ΔGHI [by SAS congruence postulate]

In ΔABC and ΔDEF

AB = DF [given]

BC = DE [ Since BC = HI  and DE = HI so by transitive property BC = DE]

m∠B =  m∠D  [given]

[ here m∠B and m∠D are the included angle of ΔABC and ΔDEF]

∴ ΔABC ≅ ΔDEF [by SAS congruence postulate]

Now, since ΔABC ≅ ΔGHI and ΔABC ≅ ΔDEF

⇒  ΔGHI ≅ ΔDEF [transitive property]

Hence, all the given triangles ΔABC, ΔDEF, and ΔGHI are con gruent to each other.

step-by-step explanation:

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.