What is the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.3? round your answer to the nearest tenth of percent

a.29.4%
b.27.4%
c.26.4%
d.28.4%

A

Step-by-step explanation:

Use the table of Z-score, considering it represnts the probability of data to the left of Z-value, the needed probability would be the subtraction of Z -0.3 to Z -1.32 value.

38.209% - 9.342% =29.867%

The neaerest answer is A

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

step-by-step explanation:

if you want to separate 54 into 6 individual tiers then you need to divide if you want to separate 54 into 6 individual tiers then you need to divide 6 and 54.

if you divide 9 by 6 you will get 54.

- hope i .