Solve

y=3x + 5

equation 1: 3x+y=53x+y=5

equation 2: 5x-4y=-35x−4y=−3 these equations for that question down below

now that we've solved for y in equation 1, it's time to substitute the resulting expression into equation 2.

what will equation 2 look like when we substitute correctly.

x=1, y=2. (1, 2).

Step-by-step explanation:

3x+y=5

5x-4y=-3

y=5-3x

5x-4(5-3x)=-3

5x-20+12x=-3

17x-20=-3

17x=-3+20

17x=17

x=17/17=1

y=5-3(1)=5-3=2

x=1, y=2.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

a

step-by-step explanation: