Atotal of 100 rats whose mothers were exposed to high levels of tobacco smoke during pregnancy were put through a simple maze. the maze required the rats to make a choice between going left or right at the outset. eighty of the rats went right when running the maze for the first time. assume that the 100 rats can be considered an srs from the population of all rats born to mothers exposed to high levels of tobacco smoke during pregnancy. (note that this assumption may or may not be reasonable, but researchers often assume lab rats are representative of such larger populations because they are often bred to have very uniform characteristics.) let p be the proportion of rats in this population that would go right when running the maze for the first time. a 90% confidence interval for p is

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺

i believe it's a.

i'm not sure on this one, most likely correct.