Mike thinks that there is a difference in quality of life between rural and urban living. he collects information from obituaries in newspapers from urban and rural towns in idaho to see if there is a difference in life expectancy. a sample of 8 people from rural towns give a life expectancy of xr¯=69.4xr¯=69.4 years with a standard deviation of sr=9.15sr=9.15 years. a sample of 5 people from larger towns give xu¯=80.3xu¯=80.3 years and su=9.48su=9.48 years. does this provide evidence that people living in rural idaho communities have different life expectancy than those in more urban communities? use a 2% level of significance.

b.) divide by -5.

step-by-step explanation:

answer: 230 miles ( vote ! )

step-by-step explanation:

180.39 minus 17.99 equals 162.4

then divide 162.4 by .80 to get 230

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;