An inspection procedure at a manufacturing plant involves picking three items at random and then accepting the whole lot if at least 2 of the three items are in perfect condition. if in reality 84% of the whole lot are perfect, what is the probability that the lot will be accepted?

We use the Binomial Distribution   where p =.84 then probability will be 0.931.

Step-by-step explanation:

P(X≥ 2) = P(X=2) + P (X=3)

           = (³₂)(.84)^2(.16) +  (³3)(.84)^3(.16)⁰

           ≅ 0.931

Hence 0.931 is the answer.

answer

a the answer hopes this

step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: