Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 132 in. find the dimensions of a rectangular package that has a square cross section and largest volume that may be sent by priority mail. hint: the length plus the girth is 4x + l.

v = 11264 in^3

Step-by-step explanation:

4 x + l =132

l=132- 4 x

v= h x^ 2

 = x ^ 2 (132 - 4 x )

= 132 x ^ 2 - 4 x^3

 = 4 ( 33 x^2 - x ^3)

d v/d x = 4 (66 x - 3 x^2)

         = 12 x ( 22 - x)

d v/d x = 0

when x = 0  or 22

So

h = 132 - 4 *22 = 44

So if the package is  44*16*16

v = 11264 in^3

So  4 x+l >= 132 But it should be minimum if 4 x+l contain smaller value

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²