Fortyforty people purchase raffle tickets. three winning tickets are selected at random. if first prize is $50005000, second prize is $45004500, and third prize is $500500, in how many different ways can the prizes be awarded?

2193360

Step-by-step explanation:

Given : Total people = 40

Number of winning tickets = 3

When we choose m things from n things in an order then we use permutations to find the number of different ways to choose them.

Number of permutations of n things taking m at a time  :-

For r= 3  and n= 40 , we have

Hence, the number of different ways can the prizes be awarded = 2193360

answer: 80,000

step-by-step explanation:

the population doubles every day.

10,000*2=20,000 day 4

20,000*2=40,000 day 5

40,000*2=80,000 day 6

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: