Ashortstop fields a grounder at a point one-third of the way from second base to third base. how far will he have to throw the ball to make an out at first base? give the exact answer and an approximation to two decimal places.

  d = 94.87 ft

Step-by-step explanation:

In a baseball game distances between bases is equal to 90 feet

Then if a shortstop get the ball one third of second base ( in the way from second base to third base) shortstop got the ball at 30 ft from second base

Now between the above mentioned point, first base and second base, we  have a right triangle. In which distance between shortstop and first base is the hypotenuse. Then

d²  =  (90)² + (30)²       d   = √ 8100 + 900       d = 94.87 ft

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4