Atrain leaves cairo at 3: 00 am, averaging 30 mph. another train headed in the same direction leaves cairo at 6: 00 am, averaging 60 mph. to the nearest tenth, how many hours after the second train leaves will it overtake the first train?

Step-by-step explanation:

Let the time of catch up be t hours after the start of second train start.

Time traveled by first train = t + (6-3) = t + 3

Speed of first train = 30 mph

Speed of second train = 60 mph

Distance traveled by first train = Distance traveled by second train

30 x ( t + 3 ) = 60 t

30t + 90 = 60t

     30 t = 30

          t = 3 hours.

After the start of second train after 3 hours second train overtakes first train.

the answer to this question is yes