Aparticular type of 4th grade achievement test provides overall scores that are normally distributed with a mean of 50 and a standard deviation of 10.
what is the probability that a randomly selected student earns a score between 33 and 48?

The probability that a randomly selected student earns a score between 33 and 48 is 0.3761

Step-by-step explanation:

We compute the z-score related to some value x as . The z-score related to 33 is given by and the z-score related to 48 is given by . Therefore, the probability that a randomly selected student earns a score between 33 and 48 is given by P(-1.7 < Z < -0.2) = P(Z < -0.2) - P(Z < -1.7) = 0.4207 - 0.0446 = 0.3761.

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step-by-step explanation:

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17