If y> x> 1, and (x^1/3 y^1/6) = 256 what is the value of xy?

xy = 2^39.

Step-by-step explanation:

8 *32 = 256

so x could be 8^3 and y could be 32^6

So xy = 8^3 * 32^6

= (2^3)^3 * (2^5)^6

= 2^9 * 2^30

= 2^39.

a

step-by-step explanation:

step-by-step explanation:

use context clues to figure out the meaning of the bolded word:  

the sage gardener knew when she had to water her plants.  

question 8 options:

mint plant

wise

happy

lazy