The frequency of vibration of a piano string varies directly as the square root of the tension on the string and inversely as the length of the string. the middle a string has a frequency of 440 vibrations per second. find the frequency of a string that has 1.25 times as much tesnsion and is 1.2 times as long.

  about 409.946 Hz

Step-by-step explanation:

The multiplier of frequency is (√(tension multiplier))/(length multiplier), so is ...

  (√1.25)/1.2 = (5/12)√5 ≈ 0.931695

So, the longer, tighter string will have the lower frequency of about ...

  0.931695×440 Hz ≈ 409.946 Hz

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.