Alas vegas handicapper can correctly predict the winning professional football team 70% of the time. the probability that she is wrong in her next prediction is 30%. for the same handicapper, find the probability that she is correct in each of her next two predictions.

0.49 or 49%

Step-by-step explanation:

The probability of the handicapper correctly predicting a single game, P(C), is 0.7, therefore, the probability of that same handicapper being correct in each of her next two predictions, P(2C) is:

The probability of her being correct in each of her next two predictions is 0.49 or 49%

step-by-step explanation:

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.