Triangle $abc$ with vertices of $a(6,2)$, $b(2,5)$, and $c(2,2)$ is reflected over the x-axis to triangle $a'b'c'$. this triangle is reflected over the y-axis to triangle $a''b''c''$. what are the coordinates of point $c''$

  C''(-2, -2)

Step-by-step explanation:

Reflection over the x-axis negates the y-coordinate. Reflection over the y-axis negates the x-coordinate. Negating both coordinates of C(2, 2) makes it ...

  C''(-2, -2)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24