Flying against the wind, an airplane travels 5760 kilometers in 6 hours. flying with the wind, the same plane travels 6300 kilometers in 5 hours. what is the rate of the plane in still air and what is the rate of the wind?

Step-by-step explanation:

Let the speed of plane be p and speed of wind be w.

Flying against the wind, an airplane travels 5760 kilometers in 6 hours.

Here

            Speed = (p-w) kmph

            Time = 6 hours

            Distance = 5760 kmph

            Distance = Speed x Time

            5760 = (p-w) x 6

               p-w = 960 eqn 1  

Flying with the wind, the same plane travels 6300 kilometers in 5 hours.

Here

            Speed = (p+w) kmph

            Time = 5 hours

            Distance = 6300 kmph

            Distance = Speed x Time

            6300 = (p+w) x 5

               p+w = 1260 eqn 2    

eqn 1 + eqn 2

                p-w + p +w =  960 + 1260

                  2p = 2220

                    p = 1110 kmph

Substituting in eqn 2

                1110 + w = 1260

                         w = 150 kmph

Speed of plane = 1110 kmph

Speed of wind = 150 kmph

i pretty sure it is

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98