The cloth top of the gazebo in mr. chang’s backyard has ripped from weathering. he needs to know the area of the cloth so he can replace it.

how much cloth, in square feet, will mr. chang need, assuming he does not need to replace the cloth at the bottom of the figure?
60
96
120
156

The correct answer is A. 60 square feet.

Step-by-step explanation:

1. Let's review the data provided to us for solving the question:

The gazebo in Mr. Chang's backyard, according to the figure, is a square pyramid because its base is a square of 6 feet as length of its sides.

Length of the sides of the base = 6 feet

Slant length = 5 feet

Height = 4 feet

2. How much cloth, in square feet, will Mr. Chang need, assuming he does not need to replace the cloth at the bottom of the figure?

Area of a square pyramid = Base area + 1/2 Perimeter * Slant length

Replacing with the real values, we have:

Area of a square pyramid = 6 * 6 + 1/2 (6 + 6 + 6 + 6) * 5

Area of a square pyramid = 36 + 1/2 (24) * 5

Area of a square pyramid = 36 + 12 * 5

Area of a square pyramid = 36 + 60

Area of a square pyramid = 96 feet ²

3. But remember than Mr. Chang doesn't need to replace the cloth at the bottom of the gazebo.

So we need to subtract the area of the base to the area of the square pyramid:

Area of the square pyramid - area of the base

Area of the base = 6 * 6 = 36 feet ²

96 feet ² - 36 feet ² = 60 feet ²

The correct answer is A. 60 square feet.

hi!

i believe that john has 55 pieces of candy left.

!

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .