Which club accepts more members each week?
which club had more founding members?
-chess
-ballet
-both

Part 1) Option B. The ballet club accept more members per week

Part 2) Option B. The ballet club had more founding members

Step-by-step explanation:

Let

x > the time in weeks

y ---> number of members

we know that

The number of members each week is equal to the slope or unit rate of the linear equation

The linear equation in slope intercept form is equal to

where

m is the slope or unit rate

b is the y-intercept or initial value

step 1

Chess Club

we have

The chess club accept 5 new member each week and it had 37 members after 6 weeks

so

substitute in the linear equation

solve for b

The linear equation is

step 2

Ballet Club

Looking at the table

take two points

(3,28) and (10,70)

so

Find the slope

we have

substitute in the linear equation

solve for b

The linear equation is

step 3

Compare the equations

Chess club

The chess club accept 5 members per week

The number of founding members (initial value or y-intercept) is 7 members

Ballet Club

The ballet club accept 6 members per week

The number of founding members (initial value or y-intercept) is 10 members

therefore

The ballet club accept more members per week

The ballet club had more founding members

answer: 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

step-by-step explanation:

other answer is correct. i had used the radius of the radius somehow. a website: